Magic 9x5 Hexagons

Magic Squares Home Magic Cube Home Site Home Page Magic Stars Home Misc. Numbers Home

rule-w.gif (2726 bytes)

S = 46  Magic Stars are normally considered to be figures of 4 numbers in a row that add to the magic constant. The magic hexagram is such a pattern, and consists of the numbers 1 to 12 arranged in 6 lines of 4 numbers such that each line sums to the constant S. The sum of the series 1 to 12 is 78, there are 6 lines with each cell appearing in 2 lines, so the magic constant (S) is (2 x 78)/6 = 26. [1]

In 1989, Harold Reiter and David Richie considered an elaboration of this figure [2].
Suppose 3 additional lines were added to the hexagram (from point to opposite point). If a number (in the series 1 to 19) is placed at each point of intersection, there will be 5 numbers on each of the 9 lines. Can these numbers be arranged in such a manner that all 9 lines total to the same value?

They found that the answer was affirmative. Their algorithm and the resulting computer search program found all possible solutions. There are actually 9 separate magic constants, ranging from 46 to 54.

This search problem was made manageable by using several short-cuts.

  1. Search for solutions with the magic constant from 46 to 50 only. Solutions for S= 51 to 54 are obtained from these by complementing the numbers (i.e. subtract each number from 20). When S=50 the complement is another solution with S=50.
  2. Consider only a standard position solution when searching. No need to consider the other 31 rotations or reflections (which are considered equivalent in magic objects).

Their search involved only 18,264,704 checks instead of the 19! that would have been required if all combinations were checked.

 The number of basic solutions are:

46

91

47

284

48

377

49

888

50

1100

51

888

52

377

53

284

54

91

Total

  4380

[1] http://www.geocities.com/~harveyh/order6.htm
[2] Harold Reiter and David Richie , A Complete Solution to the Magic Hexagon Problem, College Mathematics Journal, Vol. 20:4, 1989, pages 307-316.

 

S=47
S = 48

The S = 51 solution below is the complement of the S = 49 solution shown.

S = 49

S = 50

S = 51

 

Top.gif (1442 bytes)rule-w.gif (2726 bytes)

Please send me Feedback about my Web site!Aro_left.gif (305 bytes)Aro_up.gif (318 bytes)home07.gif (2303 bytes)Aro_right.gif (304 bytes)
Harvey Heinz   harveyheinz@shaw.ca
This page last updated April 04, 2007
Copyright © 2002 by Harvey D. Heinz