Polyiamond Variegation


In his paper Polyominoes on a Multicolored Infinite Grid, Hans Hung-Hsun Yu investigates how many colors are needed for the cells of the plane to ensure that a given polyomino has no two cells of the same color. Here I consider the corresponding problem for polyiamonds.

A polyiamond with k cells requires at least k colors. In the diagrams below, color counts that exactly meet this requirement appear in red.

For polyhexes, see Polyhex Variegation.


For the diamond two colors suffice:


For the triamond four colors are needed, to distinguish the cells of a triangle with side 2:


The same pattern admits two of the three tetriamonds:

The third tetriamond requires 6 colors, to distinguish the cells of a hexagon with side 1:


The same pattern optimally admits the I, Q, and U pentiamonds:

The fourth pentiamond requires 8 colors:


The pattern for the V tetriamond also admits five hexiamonds:

The pattern for the J pentiamond admits five other hexiamonds:

Here is the best pattern I have found for the remaining two hexiamonds.

Last revised 2018-07-19.

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Col. George Sicherman [ HOME | MAIL ]