Here I study the problem of tiling a polyomino shaped like a right trapezoid with copies of two pentominoes, using at least one of each. Such a polyomino has three straight sides, two of them parallel, and one zigzag side. For this problem, the polyomino may be triangular.
If you find a smaller solution than one of mine, please write!
See also Tiling a Right Trapezoidal Polyomino with Three Pentominoes and L Shapes from Two Pentominoes.
F | I | L | N | P | T | U | V | W | X | Y | Z | |
---|---|---|---|---|---|---|---|---|---|---|---|---|
F | * | × | × | × | 5 | × | × | × | × | × | 9 | × |
I | × | * | × | 28 | 3 | × | × | × | 39 | × | 17 | × |
L | × | × | * | 5 | 3 | × | × | × | 2 | × | 6 | × |
N | × | 28 | 5 | * | 3 | 27 | × | 9 | × | × | 7 | × |
P | 5 | 3 | 3 | 3 | * | 3 | 5 | 3 | 3 | 4 | 2 | 3 |
T | × | × | × | 27 | 3 | * | × | × | 15 | × | × | × |
U | × | × | × | × | 5 | × | * | × | × | × | 6 | × |
V | × | × | × | 9 | 3 | × | × | * | 30 | × | 20 | × |
W | × | 39 | 2 | × | 3 | 15 | × | 30 | * | × | 7 | × |
X | × | × | × | × | 4 | × | × | × | × | * | × | × |
Y | 9 | 17 | 6 | 7 | 2 | × | 6 | 20 | 7 | × | * | × |
Z | × | × | × | × | 3 | × | × | × | × | × | × | * |
Last revised 2023-12-25.